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1 Forensics Lab Series Lab 1: Exploring The Windows File System 1…. Essay Help Writer


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FORENSICS LAB SERIES
Lab 1: Exploring the Windows File System
1. 2.
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4.
5.
Getting Familiar with MFT File Viewer
Click on the CAINE graphic on the topology page to open the VM.Open a new terminal by clicking on the MATE Terminal icon located on the bottom panel.
Navigate to the /usr/local/bin directory by typing the command below followed by pressing Enter.
cd /usr/local/bin
Launch the MFT File Viewer application by entering the command below. MFTView.py /home/caine/Desktop/Windows MFT/MFT
A new MFT File Viewer screen will appear.Expand the MFT file by clicking on the arrow next to the folder icon in the left
pane.
Once expanded, notice the NTFS metadata present for the system files. In the left pane, click on the $MFT file to explore the metadata.
6.
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Lab 1: Exploring the Windows File System
7.
Once $MFT is selected, click on the Metadata tab in the middle pane.
On the Metadata tab, this is the first record or “Record 0” for the file system. Found within the MFT record are various attributes. Click on the Attributes tab.
8.
In each Record, there are attributes. The first attribute type 0x10 is called $Standard Information. Its type is 16 which is the decimal equivalent to hex value of 0x10. Its respective size is 96 bytes and the file is Resident (True) in the MFT. Resident means its size is less than 512 bytes, so it can reside in the MFT and does not have to be outside of the MFT located on the disk.
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Lab 1: Exploring the Windows File System9. Click on the Hex Dump tab to view the hex values.
10. Notice that the MFT header fields all start with File 0 at offset 0x00.
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Lab 1: Exploring the Windows File System
11. Note that the size of the MFT record located at offset 0x1c to 0x1f is the default size of 0x400 or 262144 bytes.
12. Locate the length of the header at offset 0x14 and is 0x38 or 56 bytes.
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Lab 1: Exploring the Windows File System
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Identifying Attributes with MFT File Viewer
While on the Hex Dump tab, locate where the Standard Information attribute 0x10 starts on offset 0x38.
2.
The size of the Standard Information attribute is at offset 0x04 and 0x05 from the beginning of the attribute. Its size is 0x60 or 96 bytes.
3.
Identify the creation date and time at 0x18 to 0x1F. When decoded, it can be concluded that this is stored in a Windows 64 bit hex format – Little Endian.
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Lab 1: Exploring the Windows File System
4. The last modified date and time for the file is next. Notice that the value is the same as the previous creation date and time.
5. Next is the last access date and time. Notice the same value again.
6. The next line of hex is the record access date and time. Notice the dates are the same.
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Lab 1: Exploring the Windows File System
7. Navigate to the Metadata tab and compare the values to the actual values. The hex values should match.
Click on the Attributes tab.
Identify the next attribute, 0x30 $Filename Information. Its type is 48, which is decimal for 0x30. Its respective size is 104 bytes and its resident.
10. Click on the Hex Dump tab.
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Lab 1: Exploring the Windows File System
At offset 0x98, the attribute 0x30 can be located.
Identify the size by locating bytes 0x04 and 0x05 from the 0x30. Notice the size is 68 bytes in hex, which is 104 bytes in decimal. It is also a resident record.
Click on the Attributes tab and identify the 0x80 attribute.
Notice the attribute is the $Data attribute, which is type 0x80 or 128. Its size is 72 bytes and its non-resident.
Click on the Hex Dump tab to analyze the $Data attribute more closely.
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Lab 1: Exploring the Windows File System
16. Identify offset 0x100 to locate attribute 0x80. Move to bytes 0x04 and 0x05 from there to find the size.
17. Notice that it is 48 in hex or 72 bytes in decimal. Move three more bytes to find the non-resident flag set.
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Lab 1: Exploring the Windows File System18. Notice that the end of the MFT record is at offset 0x200.
19. Click on the Attributes tab.
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Lab 1: Exploring the Windows File System20. Compare the values found from the Hex Dump tab to the Attributes tab.
21. Click on the Hex Dump tab. The last record is $Bitmap and its type 0xb0 is 176 bytes in decimal. Its size is 80 in hex and is non-resident.
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Lab 1: Exploring the Windows File System
22. Each record’s respective metadata can have multiple attributes and the same techniques that were applied in this lab can be used for each NTFS System file. As an example, click on the $Bitmap file in the left pane.
23. Navigate to the Attributes tab while having the $Bitmap file selected.
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Lab 1: Exploring the Windows File System24. Notice the resident and non-resident data is shown for each attribute when
looking through the different Records.
If the Hex Dump data cannot be seen underneath Resident, expand the window size so that the window takes up the entire screen. Once this is done, the Hex Dump data will appear.
25. Close all PC Viewers and end the reservation to complete the lab.


provide
the learning outcome of this lab above, use your original words.

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Question 4: [2 3 3 3] (CLO_3)(PLO_2) A 0.4 mm radius nonmagnetic long straight conductor carries a uniformly distributed current of 4A dc. (a) Find the current density ] within the conductor. (b) Use Ampere’s circuital law to find H and B within the conductor. (c) Show that V X H = ] within the conductor. (d) Show that V X H = ] outside the conductor. Question 5: [7] (CLO_4)(PLO_1) Write down the differential form of the Maxwell’s equations for time varying field and obtain the integral form of Maxwell’s equations using the Stokes and Divergence theorems. V . D = Pv V = – Jini E . di E = -VV C = E- F/m H = – (sin a2 – sina,)do A/m V = F = q D = EQE B = HOH ATP 4TEO R Z aR AnEO R
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Please Check Below Error. Below Is My Coding. //////// //… College Essay Help Nyc


Please check below error.

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Below is my coding.

////////// ArrayListInterface.java
// define an interface// ArrayListInterface of type T// since ArrayList of T// would implement intpublic interface ArrayListInterface {
// declare static // (since you used // ArrayListInterface.INITIAL_CAPACITY) // constant INITIAL_CAPACITY public static int INITIAL_CAPACITY = 10;
// add method definitions for // addAtIndex, addToFront, // addToBack, removeAtIndex, // removeFromFront, removeFromBack, // get, isEmpty, size, clear and // getBackingArray // do not include resizeCap // since it is already private // in ArrayList and you cannot // define a method that is // implemented in private public void addAtIndex(int index, T data); public void addToFront(T data); public void addToBack(T data); public T removeAtIndex(int index); public T removeFromFront(); public T removeFromBack(); public T get(int index); public boolean isEmpty(); public int size(); public void clear(); public Object[] getBackingArray();}
////////// Driver.java
public class Driver {
public static void main(String[] args) {
ArrayList aList = new ArrayList(); aList.addToFront(5); aList.addToFront(4); aList.addToFront(3); aList.addToFront(2); aList.addToFront(1); aList.addToBack(6); aList.addToBack(7); aList.addToBack(8); aList.addToBack(9); aList.addToBack(10);
// displays // false System.out.println(aList.isEmpty());
// displays // 10 System.out.println(aList.size());
// displays // 1 2 3 4 5 6 7 8 9 10 for (int ctr = 0; ctr < aList.size(); ctr) { System.out.print(aList.get(ctr) " "); } System.out.println(); }}
////////// ArrayList.java
import java.util.NoSuchElementException;
/*** Your implementation of an ArrayList.*/public class ArrayList implements ArrayListInterface {
// Do not add new instance variables. private T[] backingArray; private int size;
/** * Constructs a new Arraylist. */ public ArrayList() { backingArray = (T[]) new Object[ArrayListInterface.INITIAL_CAPACITY]; size = 0; }
public void addAtIndex(int index, T data) { if (index size()) { throw new java.lang.IndexOutOfBoundsException(“Index ” “greater than array size”); } if (data== null) { throw new java.lang.IllegalArgumentException(“Index ” “can’t be a null value”); } if ((size() 1) >= backingArray.length) { resizeCap(); } if (index == 0) { addToFront(data); } else if (index == size()) { addToBack(data); } else { T[] tempArr = (T[]) new Object[backingArray.length]; for (int i = 0; i < index; i ) { tempArr[i] = backingArray[i]; } for (int x = index; x < size(); x ) { tempArr[x 1] = backingArray[x]; } backingArray = tempArr; backingArray[index] = data; size ; } }
/** * Resizes the backing array’s capacity */ private void resizeCap() { T[] tempArr = (T[]) new Object[backingArray.length * 2]; for (int i = 0; i < backingArray.length; i ) { tempArr[i] = backingArray[i]; } backingArray = tempArr; }
public void addToFront(T data) { if (data == null) { throw new java.lang.IllegalArgumentException(“Index ” “can’t be a null value”); } if ((size() 1) >= backingArray.length) { resizeCap(); } if (backingArray[0] != null) { T[] tempArr = (T[]) new Object[backingArray.length]; for (int i = 0; i < size(); i ) { tempArr[i 1] = backingArray[i]; } backingArray = tempArr; } backingArray[0] = data; size ; }
public void addToBack(T data) { if (data == null) { throw new java.lang.IllegalArgumentException(“Index ” “can’t be a null value”); } if ((size() 1) >= backingArray.length) { resizeCap(); } backingArray[size()] = data; size ; }
public T removeAtIndex(int index) { T returnVal = backingArray[index]; if (index = size()) { throw new java.lang.IndexOutOfBoundsException(“Index ” “does not fit in array size”); } if (index == (size() – 1)) { return removeFromBack(); } if (index == 0) { return removeFromFront(); } T[] tempArr = (T[]) new Object[backingArray.length]; for (int i = 0; i < index; i ) { tempArr[i] = backingArray[i]; } for (int x = index; x < size() – 1; x ) { tempArr[x] = backingArray[x 1]; } backingArray = tempArr; size–;
return returnVal; }
public T removeFromFront() { if (isEmpty()) { return null; } T returnVal = backingArray[0]; T[] tempArr = (T[]) new Object[backingArray.length]; for (int i = 0; i < size() – 1; i ) { tempArr[i] = backingArray[i 1]; } backingArray = tempArr; size–; return returnVal; }
public T removeFromBack() { if (isEmpty()) { return null; } T returnVal = backingArray[size() – 1]; backingArray[size() – 1] = null; size–; return returnVal; }
public T get(int index) { if (index = size()) { throw new java.lang.IndexOutOfBoundsException(“Index ” “does not fit in array size”); } return backingArray[index]; }
public boolean isEmpty() { if (size() == 0) { return true; } return false; }
public int size() { return this.size; }
public void clear() { backingArray = (T[]) new Object[ArrayListInterface.INITIAL_CAPACITY]; size = 0; }
public Object[] getBackingArray() {
// DO NOT MODIFY return backingArray; }}

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below error is occured. Please let me know how to correct.


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